Compute each part of given question:
Question: A blue ball is thrown upward with an initial speed of 24.1 m/s, from a height of 0.8 meters above the ground. 2.9 seconds after the blue ball is thrown, a red ball is thrown down with an initial speed of 10.4 m/s from a height of 31.4 meters above the ground. The force of gravity due to the earth results in the balls each having a constant downward acceleration of 9.81 m/s2.
Part A: What is the height of the red ball 3.77 seconds after the blue ball is thrown?
Part B: How long after the blue ball is thrown are the two balls in the air at the same height?
Please use great detail in explaining the answer. Thank you.