A 500 mL sample of argon at 800 torr has it's absolute temperature quadrupled. If the volume remains unchanged what is the new pressure? The answer is 3200 torr but I am just double checking to see if I found the answer in the correct manner. I used Boyle's Law: P1 x V1= P2 x V2, P1= 800, V1= 500, P2=?, V2= 500, I then found P2 to be 800 but then I multiplied it by four to account for the absolute temperature being quadrupled in the problem. Is this correct?