A 500-ml sample of 20 x 10-4 m cuno3 is added to 500 ml of


A 50.0-mL sample of 2.0 x 10-4 M CuNO3 is added to 50.0 mL of 4.0 M NaCN. Cu+ reacts with CN- to form the complex ion [Cu(CN)3]^2:
[Cu(CN)3]^2- <--> Cu+ (+) 3CN- K = 1.0 x 10^-9 What is the concentration of CN- at equilibrium?

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Chemistry: A 500-ml sample of 20 x 10-4 m cuno3 is added to 500 ml of
Reference No:- TGS0570025

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