A 2kg block initially hangs at rest at the end of two long


A 2kg block initially hangs at rest at the end of two long strings of negligible mass as shown in the diagram below. a 150 g bullet, moving horizontally with some speed, strikes the block and appears from other side at speed of 350 m/s. after the impact, the block swings upward, but does not rotate. the maximum angular deviation of the strings from equilibrium position is 13 and period of oscillations is 3.17s. assumer that oscillations of the block can be treated as SHM of a simple pendulum. the bullet passes thorugh the block in time that is match less than period of the oscillations. calculate the length of the strings, maximum potential energy of the 2 kg block, velocity of the block immediately after the collision, velocity of the bullet just after impact, and energy lost during collision. If the length of the block is 20cm, calculate the average resistance force on the bullet inside of the block.

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Physics: A 2kg block initially hangs at rest at the end of two long
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