A 100.0 kg bungee jumper steps off a bridge with a light bungee cord tied to her and to the bridge. The unstretched length of the cord is 13.0 m. She reaches the bottom of her motion 38.0 m below the bridge before bouncing back. Her motion can be separated into an 13.0 m free-fall and a 25.0 m section of simple harmonic oscillation. (a) For what time interval is she in free-fall? 1 s (b) Use the principle of conservation of energy to find the spring constant of the bungee cord. 2 Your response differs from the correct answer by orders of magnitude. N/m (c) What is the location of the equilibrium point where the spring force balances the gravitational force acting on the jumper? Note that this point is taken as the origin in our mathematical description of simple harmonic oscillation. 3 m below the bridge (d) What is the angular frequency of the oscillation? 4 rad/s (e) What time interval is required for the cord to stretch by 25.0 m? 5 s (f) What is the total time interval for the entire 38.0 m drop? 6 s