250 mol nocl was placed in a 250 l reaction vessel at


2.50 mol NOCl was placed in a 2.50 L reaction vessel at 400ºC. After equilibrium was established, it was found that 28% of the NOCl had dissociated according to the equation

2NOCl(g)    2NO(g) + Cl2(g).

Calculate the equilibrium constant, Kc, for the reaction.

Step 1: 2.50mol / 2.50L = 1.0M

Step 2: 1.0-28%=0.72

After that I'm not sure what to do. 

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Chemistry: 250 mol nocl was placed in a 250 l reaction vessel at
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