Strength of any solution
Give me answer of this question. A solution contains 1.2046 x 1024 hydrochloric acid molecules in one dm3 of the solution. The strength of the solution is: (a) 6 N (b) 2 N (c) 4 N (d) 8 N
What are the benefits of soapy detergents over the soap less detergents? Briefly state the benefits?
In zinc blende structure, zinc atom fill up:(a) All octahedral holes (b) All tetrahedral holes (c) Half number of octahedral holes (d) Half number of tetrahedral holesAnswer: (d) In zinc blende (ZnS
Superphosphate has the formulate: CaH4 (PO4)2 H2O calculate the percentage of Phosphorus in this chemical. Show your calculations
To meet human needs, scientists have started preparing synthetic rubbers. Besides having similar properties as natural rubbers they are tougher, more flexible and more durable than natural rubber. They are capable of getting stretched to twice its length. Though, it reverts to its original shape
The constant of vander Waal's equation can be related to the coefficients of the virial equation. Vander Waal's equation provides a good overall description of the real gas PVT behaviour. Now let us
The quantum mechanical methods, illustrated previously by the Schrödinger equation, are extended by the use of operators. Or, w
Separation by distillation can be described with a boiling point diagram. The important process of distillation can now be investigated. From the boiling point diagram one can see that if a small amount of vapour were removed from a liquid of composit
These are polymers that can be broken into small segments by enzyme-catalysed reactions. The required enzymes are produced by microorganism. It is a known fact that the carbon-carbon bonds of chain growth polymers are inert to enzyme-catalysed reactions, and hence they are non biod
Provide solution of this question. To neutralise completely 20 mL of 0.1 M aqueous solution of phosphorous acid (H3 PO3) the volume of 0.1 M aqueous KOH solution required is: (a) 40 mL (b) 20 mL (c) 10 mL (d) 60 mL
Second ionization potential of Li, Be and B is in the order (a)Li>Be>B (b)Li>B>Be (c)Be>Li>B (d)B>Be>Li
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