Direction of dipole moment expected for hydrogen bromide
Illustrate the direction of the dipole moment expected for hydrogen bromide?
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An HBr molecule is linear (clearly, as it comprises two atoms only). The dipole moment is a vector, parallel to a bond, pointing to the partially positively charged atom, i.e., in this situation, hydrogen. Magnitude of the dipole moment is difference in the fractional electrical charges on every atom times the spatial separation of atoms in that bond. In a molecule with more than one bond (more than two atoms), the dipole moment of all bond must be added vectorially and the resulting vector will determine dipole moment of that molecule. For example, carbon dioxide contains two carbon-oxygen double bonds of high polarity, but because molecule is linear, and individual dipoles oppose each other, carbon dioxide molecule has no left dipole moment.
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The equilibrium constant can be treated as a particular type of molecular distribution. Consider the simplest gas-phase reaction, one in which molecules of A are converted to molecules of B. the reaction, described by the equation Q : Problem on equilibrium composition The The catalytic dehydrogenation of 1-butene to 1,3-butadiene, C4H8(g) = C4H6(g)+H2(g) is carried out at 900 K and 1 atm. Q : Question based on maximum vapour Provide solution of this question. Which has maximum vapour pressure: (a) HI (b) HBr (c) HCl (d) HF
The catalytic dehydrogenation of 1-butene to 1,3-butadiene, C4H8(g) = C4H6(g)+H2(g) is carried out at 900 K and 1 atm. Q : Question based on maximum vapour Provide solution of this question. Which has maximum vapour pressure: (a) HI (b) HBr (c) HCl (d) HF
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