Determine expression for temperature distribution


A pure aluminum conical section with Cross Sectional diameter of D= ax^(1/2). a = 0.5meters^(1/2). The small end of the cone is at x1=25mm and the large end at x2=125mm. T1=600K, T2 = 400K. The lateral surfaces are well insulated. Determine an expression for temperature distribution assuming 1D heat transfer.

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Mechanical Engineering: Determine expression for temperature distribution
Reference No:- TGS0716316

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