Problem on weight fraction
A gas contains 350 ppm of H2S in CO2 at 72°F and 1.53 atm pressure. If the gas is liquified, what is the weight fraction H2S?
Expert
Now we consider 1liter of CO2 at 72deg F {[K] ≡ (72+ 459.67) × 5/9}=295.3722 K 1.53 atm
So No moles n= PV/RT =1.53atm*1liter/(0.08205liter-atm/K-mole*295.3722) =0.063131mole
So wt of CO = 0.063131mole*28g/mole =1.76767g
Now 350 ppm H2S would have a volume 350 microlitre ( µL ) per litre, = 350 ppm =350E-6 litre
So No of moles H2S = n= PV/RT =1.53atm*(350E-6)liter/(0.08205liter-atm/K-mole*295.3722K) = 2.20959E-05 mole
The MW H2S = 34.116g/mole
So wt of H2S = 0.000753823 g
So total weight =1.768423823g
So %wt H2S = (0.0007538236/1.768423823g)*100%=0.04262%
A heater (heat source temperature = 527 K) and turbine are connected in series as shown below: Q : Calculate the pressure Calculate the Calculate the pressure at the bottom of a column of Ethanol 100 ft high using a pressure (force) balance in American Engineering Units.
Calculate the pressure at the bottom of a column of Ethanol 100 ft high using a pressure (force) balance in American Engineering Units.
I need to solve the material and energy balance for the att.
Ethanol (1) Describe the production of ethanol in Scottish Whisky beverages. Be sure to include a discussion on dangers of impurities (2) Explain the impact of ethanol on the human body (3) List th
At atmospheric pressure ethyl acetate and ethyl alcohol form an azeotropic mixture containing 53.9% mole of ethyl acetate and boiling at 71.8°C. a) Estimate the values of A & B in the empirical van Laar equation
Please can you look into this assignment and let me know if its solve able.
you look up the specific gravity of 96% H2SO4 and find it is 1.858.calculate the weight
The feed to an ammonia synthesis reactor contain 25 mole% nitrogen and the balance hydrogen. The flow rate of the stream is 3000 kg/hr. Calculate the rate of flow of nitrogen into the reactor in kg/hr. (Hint: First calculate the average molecular weight of the mixture).
The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
18,76,764
1925877 Asked
3,689
Active Tutors
1450567
Questions Answered
Start Excelling in your courses, Ask an Expert and get answers for your homework and assignments!!