Explain three different raster systems

Question

Consider three different raster systems with resolutions of 640 x 480, 1280 x 1024, and 2560 x 2048?

a) What size is frame buffer (in bytes) for each of these systems to store 12 bits per pixel?

b) How much storage (in bytes) is required for each system if 24 bits per pixel are to be stored?

Answer 1

a) Because eight bits constitute a byte, frame-buffer sizes of the systems are as follows:

1. 640 x 480 x 12 bits / 8 = 450KB;

2. 1280 x 1024 x 12 bits / 8 = 1920KB;

3. 2560 x 2048 x 12 bits / 8 = 7680KB;

b) Similarly, each of the above results is just doubled for 24 (12×2) bits of storage per pixel.