Change of power in flow of kinetic energy
Air at 20 m/s, 260 K, 75 kPa with 5 kg/s flows into a jet engine and it flows out at 500 m/s, 800 K, 75 kPa. What is the change (power) in flow of kinetic energy?
Expert
m.ΔKE = m.1/2(V2e–V2i)
= 5 kg/s×12 (5002 – 202) (m/s)21
1000 (kW/W) = 624 kW
You can consider air and in these condition the first term of the equation will be cancelled out as there will be no role of enthalpy.
Above is an e.g. Of similar question
The only consideration is of Potential energy and kinetic energy and in the question no mass flow rate is given
PV = RTV = RT/P =8.314*(100+273)/100 =31.0122
Mass Flow Rate, m = V/v = 31.0122/90=.34456
The continuity Equation(Ve2 –Vi2)/2 +g(Ze - Zi)=(Q +W)/m
Also Q = 0
Putting all the values and soling we get
W=1391.17 kw
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