--%>
Assignment Help - homework help

Networking, Distributed and Concurrent Programming

Homework Assignment : A Barbershop Problem Due: November 20, 2012 In this assignment, you are asked to write a multithreading problem to simulate the barbershop problem, which is a classical synchronization problem. The problem is taken from William Stallings's Operating Systems: Internals and Design Principles, 3rd Edition, 1998. Barber problem: Orchestrating activities in a barbershop 1. 3 chairs, 3 barbers, 1 cash register, waiting area includes 4 customers on a sofa, plus additional standing room for 7 customers. 2. A customer : • Will not enter the shop if it is filled to capacity • Takes a seat on the sofa, or stands if sofa is filled • When a barber is free, the customer waiting longest on sofa is served, the customer standing longest takes up seat on the sofa • When a customer's haircut is finished, any barber can accepted payment but because of the single cash register, only one payment is accepted at a time • Barbers divide their time between cutting hair, accepting payment and sleeping Assume the arrival rate of customers is 1 customer/3 minutes, the haircut speed of three barbers are the same 5 minutes. Initially, all three barbers are sleeping, and there is no guest in the barbershop. The output of your program is the snapshot of the barbershop at a given time (an input parameter of the program), including how many customers in the barbershop, how many are seated, how many are on the barber chairs, current status of three barbers, current status of cashier, and how many customers are dropped. Hints: • You can start from the code included in the slides, and try to solve the remaining problems (slides) step by step. • The interval of your simulation step should not larger than 1 minute. Extra credits: You can get 0.5 extra credit if you can handle the poisson arrival of customers. You can get 0.5 extra if you can handle varied hair cutting speed.

   Related Questions in Programming Languages

  • Q : Perform Exception Handling with

    On occasion, some of Brewbean’s customers mistakenly leave an item out of a basket already checked out, therefore they create a new basket containing the missing items. Though they request that the baskets be combined and hence they are not charged extra shippin

    		•
  • Q : How Java client access Corba A Corba

    A Corba remote object exists. How could you get a Java client to access this object?

    		•
  • Q : What is a Port Port: It is a number

    Port: It is a number employed by a procedure to communicate with the other procedure across a network, employing the Transmission Control Protocol (abbreviated as TCP) or User Datagram Protocol (abbreviated as UDP), for instance.

    		•
  • Q : What are Relational operators

    Relational operators: Operators, like <, >, <=, >=, == and!=, which produce a Boolean outcome, as portion of a Boolean expression.

    		•
  • Q : Class and Object and explain diverse

    Q. Define class and object with example and explain diverse specifies.  

    		•
  • Q : Grade someone activities Normal 0 false

    Normal 0 false false

  • Q : What is Control structure Control

    Control structure: A statement which affects the flow of control in a method. The typical control structures are if statements and loops.

    		•
  • Q : Explain why java is so important for

    The internet aided java to the forefront of programming. And java consequently has had a deep effect on the internet. The reason for this is highly simple: java uses the universe of objects that can travel freely in cyber space. In a network, two broad categories of

    		•
  • Q : Use the Processing program for the

    1. Here is a short program. It prints out the value of a variable "x". Ernie and Bert disagree about what will be printed: Ernie says, the value gets changed in "changeX" so it will print "7", and Bert says, no, when the function exits the changes get reversed and the value goes back to "5". Expl

    		•
  • Q : Define Livelock Livelock : It is a

    Livelock: It is a situation in which a thread waits to be notified of a condition however, on waking, finds that the other thread has inverted the condition another time. The primary thread is forced to wait again. Whenever this occurs for an indefini

    		•