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Rate at which the angular momentum is changing

A 1.53 kg particle with velocity = (9.44 m/s) - (4.84 m/s) is at x = 1.03 m, y = 6.67 m. It is pulled by a 2.10 N force in the negative x direction. About the origin, what are (a) the particle's angular momentum, (b) the torque acting on the particle, and (c) the rate at which the angular momentum is changing?

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## Q : Problem based on frictional surface of coefficient

It climbs a frictional incline of height 3 m inclined at an angle 12, then moves along a second frictional surface of coefficient 0.19 before coming to rest. The acceleration of gravity is 9.8 m/s2 .