Ka of ethanoic acid
When 5mls of 0.05M CH3COOH is allowed to react with 1.5mls of 0.05M KOH. The pH is found to be 4.43.Using the Henderson-Hasselback equation, calculate the pKa and thus the Ka of ethanoic acid.(hint :note concentrations at equilibrium*)
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The following reaction is initiated and the concentrations are measured after ten minutes: A(g) + 3 B(g) AB3(g); Kc = 1.33 x 10-2 [A] = 1.78 M [B] = 2.21 M [AB3] = 1.19 M Is the reaction in equilibrium
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