Determining inverse probability-normal distribution


The average number of miles driven in one month is normally distributed with mean (µ) of 1,400 MILES and standard deviation (σ) of 300 MILES.

An auto insurer provides discounts to drivers falling in "bottom 25%" of miles driven in month (call it an "infrequent driver" discount). What would be highest number of miles (to the nearest whole number) that motorist could drive in month and still qualify for the discount?

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Basic Statistics: Determining inverse probability-normal distribution
Reference No:- TGS020644

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