Calculate the ch3co2 in a solution that is 050 m ch3co2h


"Calculate the CH3CO2+ in a solution that is 0.50 M CH3CO2H and 0.25 M HCl (Ka CH3CO2H = 1.8 x 10^-5)" If acetic acid will not really react with a strong acid like HCl, why is the salt given as a positive ion? Isn't a hydrogen ion present too as positive?

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Chemistry: Calculate the ch3co2 in a solution that is 050 m ch3co2h
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