I need to solve the material and energy balance
I need to solve the material and energy balance for the att.
what is the latent heat of vaporization for hexane
you look up the specific gravity of 96% H2SO4 and find it is 1.858.calculate the weight
Cumene is produced by the vapour phase reaction of benzene with propylene. The fresh feeds have the following compositions: Benzene: 99% w/w benzene, 1% w/w toluene Propylene: 98% v/v propylene,
Please can you look into this assignment and let me know if its solve able.
The feed to an ammonia synthesis reactor contain 25 mole% nitrogen and the balance hydrogen. The flow rate of the stream is 3000 kg/hr. Calculate the rate of flow of nitrogen into the reactor in kg/hr. (Hint: First calculate the average molecular weight of the mixture).
At atmospheric pressure ethyl acetate and ethyl alcohol form an azeotropic mixture containing 53.9% mole of ethyl acetate and boiling at 71.8°C. a) Estimate the values of A & B in the empirical van Laar equation
A steady-state flow process is used to heat methanol in a tank. The incoming stream is at 2 bar and 25 oC and has a flow rate of 5 kg/s. The outgoing stream is at 1 bar, 100 oC. Heating is provided by a heating coil immersed in a tank. Given the
A stream of propane is throttled from 4.298 bar and 450 K to 0.22 bar. This process is irreversible due to frictional losses at the nozzle. a. In words or equations, why are frictional losses irreversible? Q : Problem on entropy A heater (heat A heater (heat source temperature = 527 K) and turbine are connected in series as shown below: Q : Problem on Clausius-Clapeyron equation The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
A heater (heat source temperature = 527 K) and turbine are connected in series as shown below: Q : Problem on Clausius-Clapeyron equation The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
The Clausius-Clapeyron equation gives us an expression for dP/dT. Now we will derive an analog to the Clausius-Clapeyron equation by obtaining an expression for dT/dµ when two phases are at equilibrium. For simplicity, let’s derive this fo
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